Autre solution, serait de pouvoir faire référence aux alias dans where clause ce qui n'est pas possible mais y a t'il moyen de contourner?
select o.id_order as numeroCommande, o.date_add as dateCommande, YEAR(o.date_add) as anneeCommande, MONTH(o.date_add) as moisCommande, oi.date_add as dateFacture, oi.number as numeroFacture, YEAR(oi.date_add) as anneeFacture, MONTH(oi.date_add) as moisFacture, gl.name as categorieClient/*, as tiersFacturé*/, c.lastname as nomContact, c.firstname as prenomContact, a.postcode as cpFacturation, a.city as villeFacturation, cl.name as paysFacturation,p.id_product, p.reference as refArticle, p.product_region as regionArticle, /* as nomDomaine,*/ od.product_name as libelleCompletProduit, od.product_quantity as quantiteCommande, od.unit_price_tax_excl as puHT, od.total_price_tax_excl as montantLigneHtNet, fvl.value as nomAppellation, fvl.value as couleur, od.original_product_price as prixAchatArticle, od.original_wholesale_price as montantLigneAchatNet from ps_order_detail od LEFT JOIN ps_orders o ON(od.id_order = o.id_order) LEFT JOIN ps_order_invoice oi ON(od.id_order = oi.id_order) LEFT JOIN ps_address a ON(o.id_address_delivery = a.id_address) LEFT JOIN ps_product p ON(p.id_product = od.product_id) LEFT JOIN ps_feature_product fp on od.product_id = fp.id_product LEFT JOIN ps_feature_value_lang fvl on fp.id_feature_value = fvl.id_feature_value LEFT JOIN ps_product_lang pl ON(pl.id_product = p.id_product) LEFT JOIN ps_customer c ON(o.id_customer = c.id_customer) LEFT JOIN ps_country_lang cl ON(a.id_country = cl.id_country) LEFT JOIN ps_customer_group cg ON(c.id_customer = cg.id_customer) LEFT JOIN ps_group_lang gl ON(cg.id_group = gl.id_group) where nomAppelation in (select fvl.value from ps_feature_value_lang fvl where fp.id_feature = 197) AND couleur in (select fvl.value as couleur from ps_feature_value_lang fvl where fp.id_feature = 133) AND o.valid = 1 AND DAY(o.date_add) = DAY(NOW() - INTERVAL 1 DAY) AND MONTH(o.date_add) = MONTH(NOW()) AND YEAR(o.date_add) = YEAR(NOW()) GROUP BY o.id_order